9x+x^2=490

Solution for 9x+x^2=490 equation:

9x+x^2=490

We move all terms to the left:

9x+x^2-(490)=0

a = 1; b = 9; c = -490;
Δ = b2-4ac
Δ = 92-4·1·(-490)
Δ = 2041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2041}}{2*1}=\frac{-9-\sqrt{2041}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2041}}{2*1}=\frac{-9+\sqrt{2041}}{2}
$